Question

find LCM and HCF of 1 upon 2 2 upon 3 and 3 upon 7​

Answer 1

Answer:

$L.C.M. of a fraction = \frac{L.C.M. OF NUMERATOR}{H.C.F. OF DENOMINATOR}$

$H.C.F. of a fraction = \frac{H.C.F. OF NUMERATOR}{L.C.M. OF DENOMINATOR}$

$L.C.M. = \frac{L.C.M. OF -1,2,3}{H.C.F. OF-2,3,7}$

$=\frac{6}{1} =6$

$H.C.F = \frac{H.C.F. OF - 1,2,3}{L.C.M. OF-2,3,7}$

$= \frac{1}{42}$

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