Find Lcm and HcF of 12,15,20,27
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Answered by
3
Answer:
12 = 2×2×3 = 2^2 ×3^1
15 = 3× 5
20 = 2×2×5 = 2^2×5
27 = 3×3×3 = 3^3
HCF = 1
LCM = 2^2 × 3^3 × 5 = 540
Answered by
0
Answer:
1
Step-by-step explanation:
12 = 3 x 4
15 = 3 x 5
20 = 2x2x5
27 =3x3x3
hcf = product of least power of common factors
therefore hcf is 1
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