find LCM and HCF of 12 and 15 by prime factorization method
Answers
SOLUTION :
SOLUTION :12 = 2 x 2 x 3 = 2² × 3¹
SOLUTION :12 = 2 x 2 x 3 = 2² × 3¹15 = 3 x 5 = 3¹ × 5¹
SOLUTION :12 = 2 x 2 x 3 = 2² × 3¹15 = 3 x 5 = 3¹ × 5¹21 = 3 x 7 = 3¹ × 7¹
SOLUTION :12 = 2 x 2 x 3 = 2² × 3¹15 = 3 x 5 = 3¹ × 5¹21 = 3 x 7 = 3¹ × 7¹L.C.M of 12, 15 and 21 = 420.
SOLUTION :12 = 2 x 2 x 3 = 2² × 3¹15 = 3 x 5 = 3¹ × 5¹21 = 3 x 7 = 3¹ × 7¹L.C.M of 12, 15 and 21 = 420.H.C.F of 12, 15 and 21 = 3.
SOLUTION :12 = 2 x 2 x 3 = 2² × 3¹15 = 3 x 5 = 3¹ × 5¹21 = 3 x 7 = 3¹ × 7¹L.C.M of 12, 15 and 21 = 420.H.C.F of 12, 15 and 21 = 3.17 = 1 x 17.
SOLUTION :12 = 2 x 2 x 3 = 2² × 3¹15 = 3 x 5 = 3¹ × 5¹21 = 3 x 7 = 3¹ × 7¹L.C.M of 12, 15 and 21 = 420.H.C.F of 12, 15 and 21 = 3.17 = 1 x 17.23 = 1 x 23.
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Answer:
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Step-by-step explanation:
LCM of 12 and 15: