Find lcm and hcf of 33 and 121 using fundamental therom
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Answered by
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33 = 3×11
121= 11×11
Hcf = 11
Lcm = 3×11×11=363
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121:11×11
HCF:11×11=121
HCF:2×2×2×2×2=32
LCM:2×2×2×2×2×2×2×3=384
ii)33:3×11
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