Question

find lcm and hcf of 8/9. .32/81..10/27

Answer 1

Hi Friend!!!

Here is ur answer !!!

LCM of 8/9 , 32/81 , 10/27 is


= LCM of numerators!/ HCF of denominators

= 2×2×2×2×2×2×5/9

= 320/9

HCF ;


HCF of numerators/LCM of denominators

= 2/3×3×3×3

= 2/81


hope it helps you : )

Answer 2

LCM = $\frac{320}{9}$ and HCF = $\frac{2}{81}$

Step-by-step explanation:

Given:

Here,

LCM of 8, 32, 10 = $2\times2\times2, 2\times2\times2\times2\times2,2\times5=2\times2\times2\times2\times2\times2\times5 = 320$

H.C.F of 9, 81, 27 = $3\times3\times,3\times3\times3\times3,3\times3\times3= 3\times3=9$

LCM = $\frac{lcm of (numerators)}{hcf of (denominators)}$

        = $\frac{320}{9}$

HCF of 8, 32, 10 = $2\times2\times2, 2\times2\times2\times2\times2,2\times5 = 2$

L.C.M of 9, 81, 27 = $3\times3\times,3\times3\times3\times3,3\times3\times3= 3\times3\times3\times3=81$

HCF = $\frac{HCF of (numerators)}{LCM of (denominators)}$

        = $\frac{2}{81}$