Question

Find lcm and hcf of (i) 96 and 128 (ii) 33 and 121 (iii) 288 and 120 using fundamental theorem of arithmetic

Answer 1

i)96:2×2×2×2×2×3
128:2×2×2×2×2×2×2
HCF:2×2×2×2×2=32
LCM:2×2×2×2×2×2×2×3=384
ii)33:3×11
121:11×11
HCF:11×11=121
LCM:11×11×3=363
iii)288:2×2×2×2×2
120:2×2×2×3×5
HCF:2×2×2×3=24
LCM:2×2×2×2×2×3×3×5=1440

Answer 2

please check this solution