Question

Find LCM and HCF of the following pairs of integers and verify that LCM×HCF= product of the two numbers 26 and 29

Answer 1

Answer:

Step-by-step explanation:

a=26=2*13

b=29=1*29

LCM(26,29)=2*13*29=754

HCF(26,29)=1

Now LCM x HCF=754*1=754

a*b=26*29=754

LCM x HCF= a x b =754

Answer 2

HCF of 26 = 2 . 13 . 1

29 = 1 . 29

HCF = 1

LCM = 2 . 13 . 29

=754

LCM . HCF = 26 . 29

1 . 754 = 26 . 29

754 = 754

Therefore the product of 26 into 29 is equal to the product of LCM and HCF