find LCM and HCF verify LCM into HCF is equal to product of number 510 and 92
Answers
Answered by
3
Using EDL
a=bq+r
where a>b
a=510 and b=92
510=92×5+50
here r ≠ 0
92=50×1+42
here also r ≠ 0
50=42×1+8
here also r ≠ 0
42=8×5+2
here also r ≠ 0
8=2×4+0
here r = 0
so, HCF of (510,92)=2
LCM=510×92/2
LCM=23460
Verification
LCM×HCF=1no×2no
23460×2=510×92
46920=46920
I HOPE THIS WILL HELP YOU MARK ME BRAINLIEST
a=bq+r
where a>b
a=510 and b=92
510=92×5+50
here r ≠ 0
92=50×1+42
here also r ≠ 0
50=42×1+8
here also r ≠ 0
42=8×5+2
here also r ≠ 0
8=2×4+0
here r = 0
so, HCF of (510,92)=2
LCM=510×92/2
LCM=23460
Verification
LCM×HCF=1no×2no
23460×2=510×92
46920=46920
I HOPE THIS WILL HELP YOU MARK ME BRAINLIEST
Answered by
3
Hello,
One Number = 510
Other Number = 92
510 = 2*2*2*2*2*2*2*2*2
92 = 2*2*23
HCF of 510 and 92 = 4
LCM of 510 and 92 = 11776.
One Number* Other Number = 512 * 92 =23552.
HCF * LCM = 23552.
Hope this will help you.
One Number = 510
Other Number = 92
510 = 2*2*2*2*2*2*2*2*2
92 = 2*2*23
HCF of 510 and 92 = 4
LCM of 510 and 92 = 11776.
One Number* Other Number = 512 * 92 =23552.
HCF * LCM = 23552.
Hope this will help you.
Similar questions