Find LCM of 12y3 – 27y and 12y2 - 6y - 18.
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Answer:
12y^3-27y=3y(4y^2-9)
=3y(2y+3)(2y-3)
12y^2-6y-18=6(2y^2-y-3)
=6[2y^2-3y+2y-3]
=6[y(2y-3)+1(2y-3)]
=6(2y-3)(y+1)
Now LCM of given expressions is 6y(y+1)(2y+3)(2y-3)
=6y(y+1)(4y^2-9)
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