Question

Find LCM of 15(2x^2-x-1) and 35(2x^2-7x+3)

Answer 1

Answer:

$L.C.M=105(2x^2-x-1)(2x^2-7x+3)$

Step-by-step explanation:

Concept used:

L.C.M of the given two polynomial is a polynomial of least degree which divides the given two polynomial exactly.

L.C.M of the given polynomial is found by factorization maethod.

$15(2x^2-x-1)$

$=3*5(2x^2-2x+x-1)$

$=3*5[2x(x-1)+1(x-1)]$

$=3*5(2x+1)(x-1)$

$35(2x^2-7x+3)$

$=5*7[2x^2-6x-x+3]$

$=5*7[2x(x-3)-1(x-3)]$

$=5*7(2x-1)(x-3)$

$L.C.M=3*5*7*(2x+1)(x-1)(2x-1)(x-3)$

$L.C.M=105(2x^2-x-1)(2x^2-7x+3)$