find LCM of 16/9 and 32/27.
(show solution also)
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Answered by
7
Heya User,
-->> 16 = 2^4
-->> 9 = 3^2
-->> 32 = 2^5
-->> 27 = 3^3
Sorry coz I mi8 have interpreted ur question the wrong way but... I'll help uh with the answer...
---> LCM ( 16, 9 ) = 2^4 * 3^2 [ Since, we have no HCF ]
= 144
---> LCM ( 32, 27 ) = 2^5 * 3^3 [ Again, we dont have no HCF ]
---> But again, if uh talk about the LCM of fractions =_=
--> U wud have been asking for the LCM of 16/9 and 32/27 :->
--> In that case :->
--> 16/9 = 48/27 and 32/27 = 32/27 [ irreducible ]
--> So, LCM [ 16 / 9 || 32 / 27 ] = ( 48/27 . 32/27 )
_____________________________________________________________
For any change in answer, just ask me...
-->> 16 = 2^4
-->> 9 = 3^2
-->> 32 = 2^5
-->> 27 = 3^3
Sorry coz I mi8 have interpreted ur question the wrong way but... I'll help uh with the answer...
---> LCM ( 16, 9 ) = 2^4 * 3^2 [ Since, we have no HCF ]
= 144
---> LCM ( 32, 27 ) = 2^5 * 3^3 [ Again, we dont have no HCF ]
---> But again, if uh talk about the LCM of fractions =_=
--> U wud have been asking for the LCM of 16/9 and 32/27 :->
--> In that case :->
--> 16/9 = 48/27 and 32/27 = 32/27 [ irreducible ]
--> So, LCM [ 16 / 9 || 32 / 27 ] = ( 48/27 . 32/27 )
_____________________________________________________________
For any change in answer, just ask me...
Shubhangi4:
thanks
Answered by
3
LCM = LCM OF NUMERATOR / HCF OF DENA MIR AT DENOMINATOR
THEREFORE THE ANSWER IS 32/9...
THEREFORE THE ANSWER IS 32/9...
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