Question

find LCM of 16/9 and 32/27.
(show solution also)

Answer 1

Heya User,

-->> 16 = 2^4
-->> 9 = 3^2 
-->> 32 = 2^5
-->> 27 = 3^3

Sorry coz I mi8 have interpreted ur question the wrong way but... I'll help uh with the answer...

---> LCM ( 16, 9 ) = 2^4 * 3^2 [ Since, we have no HCF ]
                             = 144

---> LCM ( 32, 27 ) = 2^5 * 3^3 [ Again, we dont have no HCF ]

---> But again, if uh talk about the LCM of fractions =_= 

--> U wud have been asking for the LCM of 16/9 and 32/27 :->
--> In that case :-> 
                      --> 16/9 = 48/27 and 32/27 = 32/27 [ irreducible ]
                      --> So, LCM [ 16 / 9 || 32 / 27 ] = ( 48/27 . 32/27 )

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For any change in answer, just ask me...

Answer 2

LCM = LCM OF NUMERATOR / HCF OF DENA MIR AT DENOMINATOR



THEREFORE THE ANSWER IS 32/9...