Math, asked by Anonymous, 1 year ago

Find LCM of two no. a and b whose product is 1276 and HCF is 11

Answers

Answered by Prsm08
10
HCF = 11
Product of numbers = 1276
LCM = ?

Product = HCF × LCM
1276 = 11 × LCM
LCM = 1276 ÷ 11
LCM = 116
Answered by shivamanoj
3
HCF=11

PRODUCT=1276

PRODUCT=LCM*HCF

1276=LCM*11

LCM=1276/11

LCM=116
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