find least natural number largerthan 100 which leaves the remainder 12 when divided by 19
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Answer:
107
Step-by-step explanation:
A number which leaves a remainder 12 when divided by 19 can be written as 19m+12
So 19m+12>100
===> 19m>88
===> m>4.63
So the least value of m will be m as m is a whole number
So the number is 19x5+12 = 107
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