Question

Find least no which when divided by 12, 8, 10 leaves the remainder 10, 6,8

Answer 1

Hey!!

Required number are ( 12 - 10 ) = 2 , ( 8 - 6 ) = 2 and ( 10 - 8 ) = 2

So, the required number are 2, 2 , and 2

By prime factorization method

Prime factorisation of 2 = 2 × 1

Prime factorisation of 2 = 2 × 1

Prime factorisation of 2 = 2 × 1

LCM [ 2 , 2 , and 2 ] = 0

Hope it will helps you ✌