Find least no which when divided by 12, 8, 10 leaves the remainder 10, 6,8
Answers
Answered by
2
Hey!!
Required number are ( 12 - 10 ) = 2 , ( 8 - 6 ) = 2 and ( 10 - 8 ) = 2
So, the required number are 2, 2 , and 2
By prime factorization method
Prime factorisation of 2 = 2 × 1
Prime factorisation of 2 = 2 × 1
Prime factorisation of 2 = 2 × 1
LCM [ 2 , 2 , and 2 ] = 0
Hope it will helps you ✌
Required number are ( 12 - 10 ) = 2 , ( 8 - 6 ) = 2 and ( 10 - 8 ) = 2
So, the required number are 2, 2 , and 2
By prime factorization method
Prime factorisation of 2 = 2 × 1
Prime factorisation of 2 = 2 × 1
Prime factorisation of 2 = 2 × 1
LCM [ 2 , 2 , and 2 ] = 0
Hope it will helps you ✌
Similar questions