Find least number which in exactly divisible by 32, 36, 40, 45
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The LCM of 32, 36 , 40 and 45 is 360.
Smallest 5- digit no.=10000
(Divide 10000 by 360)
The remainder is 280.
Req. no. =10000-( divisor- remainder)
=10000+(360- 280)
= 10000+ 80
= 10080
Ans. = The least no. is 10080.
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explanation is given above .......
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