Question

Find least number which in exactly divisible by 32, 36, 40, 45​

Answer 1

Answer:

The LCM of 32, 36 , 40 and 45 is 360.

Smallest 5- digit no.=10000

(Divide 10000 by 360)

The remainder is 280.

Req. no. =10000-( divisor- remainder)

              =10000+(360- 280)

              = 10000+ 80

              = 10080

Ans. = The least no. is 10080.

Answer 2

1440

explanation is given above .......

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