find least square number divisible by each one of 8,9,10
Answers
Answered by
10
Answer:
L.C.M. of 8,9,10 = 2×2×2×3×3×5=360
Since 2 and 5 are not in pairs multiply by 2 and 5 to make it a perfect square.
The required number=360×2×5=3600
The smallest square number divisible by 8,9,10=3600
Answered by
5
Answer:3600
Step-by-step explanation:LCM OF THEM IS 360
360=2*2*2*3*3*5
WE ARE TAKING SQUARE ROOT SO PAIRS FOR 2 AND 5 ARE NOT THERE
SO,360 SHOULD BE MULTIPLIED BY 2*5=10
360*10=3600
SO 3600 IS THE LEAST SQUARE NUMBER DIVISIBLE BY 8,9 AND 10.
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