Find length of a tangent drawn to a circle of radius 4cm from an external point 10cm away from the center?
Answers
Answered by
4
Hey mate,
△ORP ia a right angle triangle
∴ By using pythagoras theorem.
OP^2=OR^2+RP^2
(5)^2=(4)^2+(RP)^2
25=16+(RP)^2
(RP)^2=25−16
(RP)^2=9
RP=3cm
hope this helps you out!
△ORP ia a right angle triangle
∴ By using pythagoras theorem.
OP^2=OR^2+RP^2
(5)^2=(4)^2+(RP)^2
25=16+(RP)^2
(RP)^2=25−16
(RP)^2=9
RP=3cm
hope this helps you out!
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Answered by
10
A) 3cm3cm
Description for Correct answer:
According to question

△ORP△ORP ia a right angle triangle
∴∴ By using pythagoras theorem.
OP2=OR2+RP2OP2=OR2+RP2
(5)2=(4)2+(RP)2(5)2=(4)2+(RP)2
25=16+(RP)225=16+(RP)2
(RP)2=25−16(RP)2=25−16
(RP)2=9(RP)2=9
RP=3cm
Description for Correct answer:
According to question

△ORP△ORP ia a right angle triangle
∴∴ By using pythagoras theorem.
OP2=OR2+RP2OP2=OR2+RP2
(5)2=(4)2+(RP)2(5)2=(4)2+(RP)2
25=16+(RP)225=16+(RP)2
(RP)2=25−16(RP)2=25−16
(RP)2=9(RP)2=9
RP=3cm
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