Question

find length of the longest rod that can be put into room of (10×10×5)​

Answer 1

Answer: Rod = 5$\sqrt[3]{7}$

Step-by-step explanation:

l = 10 b = 10 h = 5

Diagonal = $l^3+b^3+h^3$

= $10^3+10^3+5^3$

=1000+1000+125

=2125

=5$\sqrt[3]{7}$

Answer 2

Answer:

l = 10 b = 10 h = 5

Diagonal = l3+b3+h3l3+b3+h3

= 103+103+53103+103+53

=1000+1000+125

=2125

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