Question

find length when width is 50 cm and the perimeter of rectangle is 100​

Answer 1

Answer:

0cm

Step-by-step explanation:

perimeter of rectangle= 2(l+b)

100=2(L+50)

50=l+50

l= 50-50

=0cm

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Answer 2

$\huge{ \underline{ \bf{Given \: : }}}$

• Width is 50 cm
• Perimeter of the rectangle is 100 cm

$\huge{ \underline{ \bf{To \: Find \: : }}}$

• The length of the rectangle

$\huge{ \underline{ \underline{ \mathrm{Solution \: : - }}}}$

As we know,

The perimeter of the rectangle

$\large{\purple\star}{ \small{ \red{ \underline{ \underline{ \boxed{ \tt{ \green{perimeter = 2(length + breadth)}}}}}}}}$

Now on substituting the values,

$\\ \to \tt100 = 2(length + 50)$

$\\ \tt \to \cancel\frac{100}{2} = length + 50$

$\\ \tt \to50 = length + 50$

$\\ \tt \to \: length = 50 - 50$

$\\ \tt \to \: length = 0$

$\tt \therefore \: length = \color{gold}{ 0 \: cm}$

Therefore, the length of the rectangle is 0 cm.