find length 'x' in the following figure.
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Answered by
0
Using pythagoras theorem
AC²=AD²+DC²
DC²=AC²-AD²
=2500-196
=2304
DC=48
In same way BD also
48+48=96
AC²=AD²+DC²
DC²=AC²-AD²
=2500-196
=2304
DC=48
In same way BD also
48+48=96
Answered by
1
x/2=√50²-14²
x/2=√2500-196
x/2=√2304
x=2√2304
x/2=√2500-196
x/2=√2304
x=2√2304
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