Question

Find lim->1 (x^7-2x^5+1)/(x^3-3x^2+2)

Answer 1

Thanks for watching the answer.
Practice the limits chapter to become expert in this chapter.
Keep going, you will be Master in this chapter

Answer 2

$\fontsize{18}{10}{\textup{\textbf{The value of the given limit is 0.}}}$

Step-by-step explanation:  The given limit is

$L=\lim_{x\rightarrow 1}\dfrac{x^7-2x^5+1}{x^3-3x^2+2}.$

We see that, when we put x = 1 in the above limit, then the fraction becomes of the form $\frac{0}{0}.$

So, we will be using L' Hospital's rule to calculate the given limit. That is, we go on differentiating the numerator and denominator until we get some definite value.

Therefore, we have

$L\\\\\\=\lim_{x\rightarrow 1}\dfrac{x^7-2x^5+1}{x^3-3x^2+2}~~~[\frac{0}{0}]\\\\\\=\lim_{x\rightarrow 1}\dfrac{7x^6-10x^4}{3x^2-6x}\\\\\\=\lim_{x\rightarrow 1}\dfrac{7x^5-10x^3}{3x-6}\\\\\\=\dfrac{7\times0-10\times0}{3\times0-6}\\\\=0.$

Thus, the value of the given limit is 0.

Learn more#

Question :Find  Lim x tends to 5 log x-log 5/x-5.

Link : https://brainly.in/question/9491447.