Question

find lim x tend
$lim x \: tend \: to \: 0 \: \frac{ \sqrt{1 + x } - 1}{2x}$
to 0 √(1+x) -1/2x​

Answer 1

Answer:

1/4

Step-by-step explanation:

${ \lim_{x \to0 } \frac{\sqrt{1+x}-1 }{2x} \\\\By applying L'Hopitals Rule,\\={ \lim_{x \to0 }\frac{\frac{1}{2\sqrt{1+x} } }{2}\\=\frac{1}{4}$