Math, asked by galande, 11 months ago

find limit by using l hospital rule for limx-0 x^2-sin^2x÷x^4​

Answers

Answered by msasomrat
1

Answer:

0

Step-by-step explanation:

x²-sin²x\x^4

2x-2sinxcosx\4x³

2-co2x*2\12x²

4sin2x\24x

8cos2x\24

if we input limit the answer is 0

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