Question

find limit of (1-cos2x)/x^2 with x--->0

the right answer will marked as brainlist​

Answer 1

Answer:

1

Step-by-step explanation:

limit of ( 1-- cos2x)/x^2 x tends to zero.

By L Hospital's Rule ,

Lt 2sin^2x/ 2x = Sin2x/2 = 2cos2x/2 = 1

x --0 x --0, x--0

Ans . the required limit is 1.