Question

Find load of a wire of cross section 16mm2 to increase in length 3%

Answer 1

Answer:

Explanation:

NL/SdL=Y

N=YSdL/L

dL/L=3/100

S=16*10^-6m2

Y youngs modulus

N=4.8*10^-3*Y newton

Answer 2

∆L = FL/AY

Given that,

A = 16mm²

∆L/L = 3%

Hence,

∆L/L = F/AY

Put the values in and you can get the answer

I cannot find the answer because the value of Y is not given by you

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