Find local minimun value of the
function 'f' given by f(x)= 3+1*1,x€r
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Answer:
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There is two answer in two one was right
First
Answer is 3
ANSWER
Fact: Absolute value of any number will always non-negative
⇒∣x∣≥0∀x∈R
Therefore f(x)=3+∣x∣≥3+0=3
Hence minimum value of the given function is 3
second
ANSWER
(i)f(x)=∣x−2∣−1
Minimum value of ∣x−2∣=0
Minimum value of f(x)=minimum value of ∣x−2∣−1
=0−1=−1
Minimum value of f(x)=−1→(x=−2)
f(x) has no maximum value.
(ii)f(x)=−∣x+1∣+3
∣x+1∣>0
⇒−∣x+1∣<0
Maximum value of g(x)=maximum value of −∣x+1∣+3
=0+3=3
Maximum value of g(x)=3
There is no minimum value of g(x)
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