Question

find log 3^2 +log2/3 ? i will mak as brainliest

Answer 1

$log {m}^{n} = nlogm$
$log \frac{m}{n} = logm - logn$

log3^2+log2/3

2log3+log2-log3

log2+log3

log6

log6=0.7781512503