Question

find lower boundary and upper boundary of a class interval whose mid value is 30 and width is 20​

Answer 1

Step-by-step explanation:

10−19,20−29,30−39,...

Here the class intervals are not continuous. To make them continuous take the mean of upper limit of first class and lower limit of second class.

Mean =

2

19+20

=19.5, which gives the upper limit of first class and lower limit of second class for the continuous class intervals.