Question

Find lowest number between 200 and 500 which leaves a remainder of 3 in each case when divided by 8,10,12 and 30

Answer 1

Step-by-step explanation:

firstly we need the lcm of 8 ,10, 12,30

2[ 8,10,12,30]

3[4,5,6,15]

5 [4,5,2,5]

2 [4,1,2,1]

2,1,1,1

the lcm of 8,10,12,30= 2*3*5*2*2

=120

multiply 120 with a number so that the product is between 200 and 500 and is lowest.= 120* 2= 240

therefore the lowest number between 200 and 500 which leaves a remainder 3= 240+3 = 243

hope this answer your question