Math, asked by abhilash4360, 8 months ago

find LSA of a cuboid whose length is 10 cm breadth is 5 cm and height is 3 cm​

Answers

Answered by hriday1804
0

Answer:

90cm²

Step-by-step explanation:

Given

l=10cm

b=5cm

h=3cm

LSA=2h(l+b)

=2×3(10+5)

=6(15)

=90cm²

Answered by shaktisrivastava1234
40

 \huge   \underline{\red{\boxed{\bold{Correct \:  Question:}}}}

 \sf{Find \: the \: L.S.A. \: of \: cuboid \: whose \: dimension \: {is \: 10cm \times 5cm \times 3cm.}}

 \huge   \underline{\red{\boxed{\bold{Answer:}}}}

 \large \underline {\bf{Given}}

  \mapsto\sf{Length \:  of \:  cuboid \:  is   \: \bf{10cm.}}

  \mapsto\sf{Breadth \:  of \:  cuboid \:  is   \: \bf{5cm.}}

  \mapsto\sf{Height \:  of \:  cuboid \:  is   \: \bf{3cm.}}

 \large \bf \underline{To  \: find}

 \sf \leadsto{Lateral \:  surface  \: area(L.S.A.)  \: of  \: cuboid.}

 \large \bf \underline{Formula \:  required:}

  \underline{\blue {\boxed{ \sf{Lateral \:  surface  \: area (L.S.A.)  \: of \:  cuboid=2(length + breadth) \times height}}}}

 \large \bf \underline{According  \: to  \: Question:}

\sf{ \implies{Lateral \:  surface  \: area (L.S.A.)  \: of \:  cuboid=2(length + breadth) \times height}}

\sf{ \implies{Lateral \:  surface  \: area (L.S.A.)  \: of \:  cuboid=2(10+5) \times 3}}

\sf{ \implies{Lateral \:  surface  \: area (L.S.A.)  \: of \:  cuboid=2 \times 15\times 3}}

\sf{ \implies{Lateral \:  surface  \: area (L.S.A.)  \: of \:  cuboid=90 {cm}^{2} }}

 \large \underline{ \bf{Know  \: more:}}

 \boxed{ \begin{array}{|l|l|} \hline  \sf T.S.A  \: of  \: cuboid& \sf 2(lb+bh+hl) \\  \hline \sf Diagonal  \: of \:  cuboid&  \sf\sqrt{ {l}^{2}  +  {b}^{2}  +  {h}^{2} }  \\  \end{array}}

 \small \bf{Note:}

 \sf{Here,we \: use  \: {\bf{l}}, {\bf{b}} \: and  \: {\bf{h}} \: to \: represent \: length,}

  \sf{ {\bf{breadth}} \: and  \: {\bf{height}} \: of \: the \: cuboid.}

_________________________________________________________

Similar questions