Question

find LSA of a cuboid whose length is 10 cm breadth is 5 cm and height is 3 cm​

Answer 1

Answer:

90cm^2

Step-by-step explanation:

Lateral surface area of cuboid

$2(l + b) \: h$

2 ( 10 + 5 ) 3

6* 15

= 90 cm^2

Answer 2

$\huge \underline{\red{\boxed{\bold{Correct \: Question:}}}}$

$\sf{Find \: the \: L.S.A. \: of \: cuboid \: whose \: dimension \: {is \: 10cm \times 5cm \times 3cm.}}$

$\huge \underline{\red{\boxed{\bold{Answer:}}}}$

$\large \underline {\bf{Given}}$

$\mapsto\sf{Length \: of \: cuboid \: is \: \bf{10cm.}}$

$\mapsto\sf{Breadth \: of \: cuboid \: is \: \bf{5cm.}}$

$\mapsto\sf{Height \: of \: cuboid \: is \: \bf{3cm.}}$

$\large \bf \underline{To \: find}$

$\sf \leadsto{Lateral \: surface \: area(L.S.A.) \: of \: cuboid.}$

$\large \bf \underline{Formula \: required:}$

$\underline{\blue {\boxed{ \sf{Lateral \: surface \: area (L.S.A.) \: of \: cuboid=2(length + breadth) \times height}}}}$

$\large \bf \underline{According \: to \: Question:}$

$\sf{ \implies{Lateral \: surface \: area (L.S.A.) \: of \: cuboid=2(length + breadth) \times height}}$

$\sf{ \implies{Lateral \: surface \: area (L.S.A.) \: of \: cuboid=2(10+5) \times 3}}$

$\sf{ \implies{Lateral \: surface \: area (L.S.A.) \: of \: cuboid=2 \times 15\times 3}}$

$\sf{ \implies{Lateral \: surface \: area (L.S.A.) \: of \: cuboid=90 {cm}^{2} }}$

$\large \underline{ \bf{Know \: more:}}$

$\boxed{ \begin{array}{|l|l|} \hline \sf T.S.A \: of \: cuboid& \sf 2(lb+bh+hl) \\ \hline \sf Diagonal \: of \: cuboid& \sf\sqrt{ {l}^{2} + {b}^{2} + {h}^{2} } \\ \end{array}}$

$\small \bf{Note:}$

$\sf{Here,we \: use \: {\bf{l}}, {\bf{b}} \: and \: {\bf{h}} \: to \: represent \: length,}$

$\sf{ {\bf{breadth}} \: and \: {\bf{height}} \: of \: the \: cuboid.}$

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