find <A in the figure if AOB is diameter <B=40
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angle a is 50 degree
ddgbvRiya1:
wlcm
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angle B = 40
angle C =90° (because angle subtended from the diameter is always 90°)
By angle sum property of triangle:
angle A + angle B + angle C = 180°
angle A + 40 + 90 = 180°
angle A = 180 - (90+40)
= 180 - 130
=50°
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angle C =90° (because angle subtended from the diameter is always 90°)
By angle sum property of triangle:
angle A + angle B + angle C = 180°
angle A + 40 + 90 = 180°
angle A = 180 - (90+40)
= 180 - 130
=50°
(≧▽≦)
Plz mark as brainliest....
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