Question

) Find <AOC from figure
A
30
B 50
55​

Answer 1

$\huge\fcolorbox{red}{yellow}{Hello}$

Here is your answer

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We are given that AB is a chord of a circle and AOC is its diameter such that  ACB = 50°.

Also, AT is the tangent to the circle at point A.

As we can clearly see in the figure that ABC is a right-angled triangle with right angle at B. So, the sum of all angles of a triangle is equal to 180°.

In ABC ;

ABC + BAC + ACB = 180°

90° + BAC + 50° = 180°

140° + BAC = 180°

BAC = 180° - 140° = 40°.

Now, we are given that AT is the tangent to the circle at point A, this means;

BAC + BAT = 90°    {beacuse tangent is perpendicular to the radius}

40° + BAT = 90°

BAT = 90° - 40° = 50°.

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Hope it helps! ^_^

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