Find m∠ADB in rhombus ABCD if m∠ACB=40°.
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Answer:
m angle ADB= 50°
Step-by-step explanation:
angle A= angle C -( opposite sides of a rhombus)
also, angle B= angle D -(opposite sides of a rhombus)
angle ACB=40°=1/2 angle C.
therefore angle C =40°×2
=80°
therefore angle A=angle C=80°
Hence, angles (A+B+C+D)=360°
therefore angles (80°+B+80°+D)=360°
but, angle B= angle D -(opposite sides of rhombus)
so, angles (160°+2D)=360°
2D=360°-160°
2D=200°
D=100°
but, angle ADB = angle CDB. angle D= angle ADB + angle CDB
100°=2 angle ADB
50°=angle ADB
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