Find m and n, if (m+n)P2, = 56 and (m-n)P2 = 12.
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(m+n)P2=56
=>(m+n)!/(m+n-2)!=56
=>(m+n)*(m+n-1)=8*7
Therefore, m+n=8_______1
(m-n)P2=12
=>(m-n)!/(m-n-2)!=12
=>(m-n)(m-n-1)=12
=>(m-n)(m-n-1)=4*3
Therefore, m-n=4______2
Adding 1 and 2 we get,
2m=12
=>m=6
Therefore, n=2
=>(m+n)!/(m+n-2)!=56
=>(m+n)*(m+n-1)=8*7
Therefore, m+n=8_______1
(m-n)P2=12
=>(m-n)!/(m-n-2)!=12
=>(m-n)(m-n-1)=12
=>(m-n)(m-n-1)=4*3
Therefore, m-n=4______2
Adding 1 and 2 we get,
2m=12
=>m=6
Therefore, n=2
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