Math, asked by sheelaravibharathi, 11 months ago

find m and n if x⁴-8x³+mx²+nx+16​

Answers

Answered by bhoomikasamraj
4

Answer:

24, - 32

Step-by-step explanation:

Given

find the square root of x^4-8x^3+mx^2+nx+16 and also find the value of m and m

Now we need to find the square root of the given expression

so. x^2-4x+ (m-16)/2

--------------------------------------------------

x^2 x^4 - 8x^3+mx^2+nx+16

2x^2-4X x^4

-----------------------------------------------------

-8x^3+mx^2

-8x^3+16x^4

--------------------------------------------------------

2x^2-8X +(m-16)/2. (m-16)x^2+nx+16

(m-16)x^2- 4 (m-16)X +[m-16/2]^2

Equating th constant term we get

[(m-16)/2]^2=16

(m-16)/2=4

m-16=8

m=8+16

m=24

By equating coefficients of X we get

n= - 4(m-16)

n= - 4(24-16)

n= - 4*8

n= - 32

Similar questions