Question

find M and N so that the following number is divisible by both 3 and 5. a) M56N, b) 45M7N, c) N608M​

Answer 1

Answer:

A)m=2,n=5

B)m=2,n=0

C)m=2,n=5

Step-by-step explanation:

Answer 2

Step-by-step explanation:

for division by 5

a) N = 0,5

for N=0

M+5+6+0= multiple of 3

11+M= multiple of 3

M is a digit having value from 0 to 9

11+M has value from 11 to 20

11+M=12,15,18

M =1,4,7

for N=5

M+5+6+5= mutiple of 3

M+16=mutiple of 3

M+16 has value from 16 to 25

M+16=18,21,24

M=2,5,8

b)

N=0,5 for divisibility by 5

N=0

M+4+5+7+0=multiple of 3

M+16= multiple of 3

M+16 has value from 16 to 25

M+16=18,21,24

M=2,5,8

for N=5

M+4+5+7+5= multiple of 3

M+21= multiple of 3

M+21 has value from 21 to 30

M+21=21,24,27,30

M=0,3,6,9

c)

M=0,5

for M=0

N+6+0+8+0= multiple of 3

N+14=multiple of 3

N+14 has value from 14 to 23

N+14=15 ,18,21

N=1,4,7

for M=5

N+6+0+8+5= multiple of 3

N+19= multiple of 3

N+19 has value from 19 to 28

N+19 =21,24,27

N=2,5,8