find m angle 5 when m angle 3=70°
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Two parallel lines l and m be cut by a transversal t, forming angles. It is given that ∠5 = 70°. Now, ∠5 = ∠3 = 70° … [∵ alternate interior angles] ∠5 + ∠8 = 180° … [∵ linear pair] 70° + ∠8 = 180° ∠8 = 180° – 70 ∠8 = 110° ∠1 = ∠3= 70° … [∵ vertically opposite angles] ∠3 + ∠4 = 180° … [∵ linear pair] 70 + ∠4 = 180° ∠4 = 180° – 70° ∠4 = 110° ∴ ∠1 = 70°, ∠3 = 70°, ∠4 = 110° and ∠8 = 110°.Read more on Sarthaks.com - https://www.sarthaks.com/751719/in-the-given-figure-and-transversal-5-70-find-the-measure-of-each-of-the-angles-1-3-4-and?show=751722#a751722
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