Question

Find :m(arc AXP) and m(arc PAB )
...Please find this answer it's very important​

Answer 1

Answer:

Given: seg AB is a diameter, seg CD bisects ∠ACB.

To prove: seg AD ≅ seg BD 

Construction: Draw seg OD.

  Proof:  ∠ACB = 90° [Angle inscribed in a semicircle] 

∠DCB = ∠DCA = 45° [CD is the bisector of ∠C] 

m(arcDB) = 2∠DCA = 90° [Inscribed angle theorem] 

∠DOB = m(arc DB) = 90° ………… (i) [Definition of measure of arc]

segOA ≅ segOB …………. (ii) [[Radii of the same circle] 

∴ line OD is the perpendicular biscctor of [From (i) and (ii)] 

seg AB.

∴ seg AD ≅ seg BD

Step-by-step explanation:

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