Question

Find m for the following function if f(m)=0 f(m) = 6m - 6 =​

Answer 1

Answer:

Let,

f(x)=x2+mx+(m2+6m)

As per  question given that exactly one root of the equation lies between  -2 and 0.

Hence, only one is negative.

Therefore f(−2)×f(0)<0

Putting the value in the function ,we get

[(−2)2−2m+m2+6m]×[m2+6m]<0

⇒[m2+4m+4]×m(m+6)<0

⇒(m+2)2×m×(m+6)<0

Hence, the range of m becomes

m∈(−6,0)−{−2,}

We can write it as

m∈(−6,−2)∪(−2,0)

Hence, this is the answer .

Answer 2

Answer:

ACCORDING TO QUESTION:

EQUATING BOTH FUNCTIONS

6m-6=0

6m=6

m=1

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