Question

find ‘m’ for which (x+3) is a factor of x²+mx+15​

Answer 1

Answer:

x + 3 = 0

x = -3

x^2 + MX + 15

(-3)^2 + m(-3) + 15 = 0

9 - 3m + 15 = 0

24 -3m = 0

-3m = -24

m = -24/-3

m = 8

therefore the Value of x = 8

I think this is the answer...........I hope it helps you

Answer 2

The value of m is 8.

Given:

An equation x²+mx+15​.

To Find:

The value of 'm' for which (x+3) is a factor of x²+mx+15​.

Solution:

It is given that (x+3) is the factor of x²+mx+15​. As we know that if (x-p) is a factor of ax²+bx+c​, then ax²+bx+c at (-p) is equal to 0.

Substitute -3 for x into x²+mx+15​ and simplify.

$(-3)^2+m(-3)+15=0\\9-3m+15=0\\3m=24\\m=8$

Thus, the value of m is 8.

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