Math, asked by sshauryaabhusri77, 9 months ago

Find m if:(15/19)^3 × (15/19)^6 = (15/19)^2m-1

Answers

Answered by shiny38
0

Answer:

(15/19)^3×(15/19)^6=(15/19)^2m-1

3+6=2m-1

therefore m=5

Answered by shilpanagpal2
2

Answer:

m = 5

Step-by-step explanation:

given : (15 )^3 × (15/19 ) ^6 = (15 /19)^2m -1

ans ::::: (15 /19)^3+6= (15/19 )^2m-1

:::::::::::: (15 /19)^9 = (15/19 ) ^ 2m - 1

:::::::::::: base are same

:::::::::::: 9 = 2m - 1

:::::::::::: 9 + 1 = 2m

:::::::::::: 10 = 2m

:::::::::::: m = 10 /2

:::''::::::::: m = 5

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