Find 'm' if (-3)^m+1*(-3)^5=(-3)^7
Answers
Answered by
7
Using m^a*m^b=m^a+b
(-3)^m+1*(-3)^5 = (-3)^7
(-3)^ m+5 = (-3)^7
or
m+1+5 = 7
m =7-6
m= 1 Ans.............
(-3)^m+1*(-3)^5 = (-3)^7
(-3)^ m+5 = (-3)^7
or
m+1+5 = 7
m =7-6
m= 1 Ans.............
Answered by
3
Since the base is same calculate the powers alone
M+1*5=7
Power law
M+1+5=7
M+1=7-5
M+1=2
M=2-1=1
Therefore m=1
U can check it also
-3^2*-3^5=-3^7
Again substitute the powers as base is Sam e
2+5=7
LHS= RHS
WHICH showes that the answer is correct
Therefore the final answer
M=1
Hope in helped u
M+1*5=7
Power law
M+1+5=7
M+1=7-5
M+1=2
M=2-1=1
Therefore m=1
U can check it also
-3^2*-3^5=-3^7
Again substitute the powers as base is Sam e
2+5=7
LHS= RHS
WHICH showes that the answer is correct
Therefore the final answer
M=1
Hope in helped u
Similar questions
English,
8 months ago
Social Sciences,
8 months ago
Biology,
1 year ago
Biology,
1 year ago
Science,
1 year ago