Find m if (m-12) x² +2(m-12) x+2=0 as real and roots equal
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Answer:
Given,
equal and real roots ⇒b2−4ac=0
∴b2=4ac
a=(m−12),b=2(m−12),c=2
[2(m−12)]2=4(m−12)(2)
4(m−12)2=4(m−12)(2)
(m−12)2−2(m−12)=0
(m−12)(m−12−2)=0
∴m=14,12
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