Find m if (m-12)x²+2(m-12)x+2=0 has real and equal roots.
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Answered by
3
Step-by-step explanation:
for real and equal root determinant should be equal to zero
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Answered by
1
Answer:
Given,
equal and real roots ⇒b
2
−4ac=0
∴b
2
=4ac
a=(m−12),b=2(m−12),c=2
[2(m−12)]
2
=4(m−12)(2)
4(m−12)
2
=4(m−12)(2)
(m−12)
2
−2(m−12)=0
(m−12)(m−12−2)=0
∴m=14,12
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