find m if (m-12)x²+2(m-12)x+2=0 hase a real and equal roots
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1
Answer:
Given,
equal and real roots ⇒b2 −4ac=0
∴b2 =4ac
a=(m−12),b=2(m−12),c=2
[2(m−12)] 2 =4(m−12)(2)
4(m−12) 2 =4(m−12)(2)
(m−12) 2 −2(m−12)=0
(m−12)(m−12−2)=0
∴m=14,12
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Answered by
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Answer:
m=14
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