Question

Find m if (m-12)x² +(m-12)x+2=0, has real and equal roots.​

Answer 1

Answer:

Given,

equal and real roots ⇒b

2

−4ac=0

∴b

2

=4ac

a=(m−12),b=2(m−12),c=2

[2(m−12)]

2

=4(m−12)(2)

4(m−12)

2

=4(m−12)(2)

(m−12)

2

−2(m−12)=0

(m−12)(m−12−2)=0

∴m=14,12