Question

Find m if p (2)= p(- 1) for p(x) = x3 -2mx2-x+2​

Answer 1

Answer:

(i) p(y)=y2−y+1

p(0)=(0)2−(0)+1=0+0+1=1

p(1)=(1)2−(1)+1=1−1+1=1

p(2)=(2)2−(2)+1=4−2+1=3

(ii) p(t)=2+t+2t2−t3

p(0)=2+(0)+2(0)2−t3=2+0+0−0=2

p(1)=2+(1)+2(2)2−(1)3=2+1+2−1=4

p(2)=2+(2)+2(2)2−(2)3=2+2+8−8=4

(iii) p(x)=x3

p(0)=(0)3=0

p(

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