Find m if the ordinate and anscissa of the point (6m, m^2+5m - 12) are equal
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Solution :
According to the problem
given,
6m = m²+5m-12
=> 0 = m²+5m-12-6m
=> m²-m-12=0
=> m² -4m + 3m - 12 = 0
=> m( m - 4 )+3( m - 4 ) = 0
=> ( m-4 )( m + 3 ) = 0
=> m - 4 = 0 or m + 3 = 0
=> m = 4 or m = -3
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