Question

find m if the quadratic equation x2-2(m+1)x+m2=0 has real and equal roots​

Answer 1

Answer:

Value of m is -1/2.

Step-by-step explanation:

A quadratic equation

$a {x}^{2} + bx + c = 0$

has real and equal roots, if its determinant , say D,

$D = {b}^{2} - 4ac = 0$

Comparing with the given equation, we have

${ (- 2(m + 1))}^{2} - 4 \times 1 \times {m}^{2} = 0 \\ \implies 4 {(m + 1)}^{2} - 4 \times {m}^{2} = 0 \\ \implies 4({(m + 1)}^{2} - {m}^{2} ) = 0 \\ \implies 4(1 + 2m) = 0 \\ \implies m = \frac{ - 1}{2} .$